Correct Answer:
Option D - 4+6×2–27÷3=8×2–4+9÷3
On interchanging 6 and 8 in the given equation from option (d),
4+8×2–27÷3=6×2–4+9÷3
4 + 16 – 9 = 12 – 4 + 3
20 – 9 = 15 – 4
11 = 11
D. 4+6×2–27÷3=8×2–4+9÷3
On interchanging 6 and 8 in the given equation from option (d),
4+8×2–27÷3=6×2–4+9÷3
4 + 16 – 9 = 12 – 4 + 3
20 – 9 = 15 – 4
11 = 11